5=-5t^2+10t

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Solution for 5=-5t^2+10t equation: 



5=-5t^2+10t

We move all terms to the left:

5-(-5t^2+10t)=0

We get rid of parentheses

5t^2-10t+5=0

a = 5; b = -10; c = +5;
Δ = b2-4ac
Δ = -102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{10}{10}=1$

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